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Allow variable word count, introduce -w argument.

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nicholas 2018-09-04 13:11:17 -04:00
parent 7e3bde7e0b
commit fcbb45905d
1 changed files with 10 additions and 3 deletions
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passphrase
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@ -7,6 +7,7 @@
SPACE=0 # default to no spaces between words SPACE=0 # default to no spaces between words
COUNT=1 # default to one group of passphrases COUNT=1 # default to one group of passphrases
WORDS=3 # default to three-word phrases
echo "" echo ""
@ -28,6 +29,12 @@ while [[ $# > 0 ]]; do # iterate through arguments, one or two steps at a time
shift shift
;; ;;
-w) # we are specifying a word count
WORDS="$2"
# skip the argument; see above
shift
;;
*) *)
# we were given an argument we don't understand or don't care # we were given an argument we don't understand or don't care
# about. Let's just... ignore it completely, shall we? # about. Let's just... ignore it completely, shall we?
@ -38,7 +45,7 @@ while [[ $# > 0 ]]; do # iterate through arguments, one or two steps at a time
done done
if [ "$COUNT" -lt 1 ]; then if [ "$COUNT" -lt 1 ] || [ "$WORDS" -t 1 ] ; then
echo -e "Don't be cheeky.\n" echo -e "Don't be cheeky.\n"
@ -48,9 +55,9 @@ for (( z = 1; z <= $COUNT; z++ )); do # give us COUNT groupings of five passphra
for i in {1..5}; do for i in {1..5}; do
PASSPHRASE=`grep "^[a-z]\{3,8\}$" /usr/share/dict/words | shuf -n3` PASSPHRASE=`grep "^[a-z]\{3,8\}$" /usr/share/dict/words | shuf -n$WORDS`
# select all words from the standard linux words file with a length between # select all words from the standard linux words file with a length between
# 3 and 8 characters. Give us three of those words at random. # 3 and 8 characters. Give us some of those words at random.
if [ "$SPACE" -eq 0 ]; then # if we want spaces stripped if [ "$SPACE" -eq 0 ]; then # if we want spaces stripped